$\begin{cases}x(4y^{3}+3y+\sqrt{5y^{2}-x^{2}})=y^{2}(x^{2}+4y^{2}+8) \\ x+\sqrt{12-2x}=2y^{2}-2\sqrt{y}-4 \end{cases}$
KHÓ QUÁ!!!!!!!!!!!!!!!!!!!!!!!
$\begin{cases}x(4y^{3}+3y+\sqrt{5y^{2}-x^{2}})=y^{2}(x^{2}+4y^{2}+8) \\ x+\sqrt{12-2x}=2y^{2}-2\sqrt{y}-4 \end{cases}$
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